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select pd.Series type from a list
I need to select the type of a series
here is what I tried
data=pd.DataFrame(df[['id','Age']])
d=data.select_dtypes(include=['int'])
error
TypeError: select_dtypes() got an unexpected keyword argument 'include'
tried different ways to include only 'int'
what am I doing wrong?
A:
The error you're getting is due to the presence of the argument 'include' in the function select_dtypes(). It's not an error.
The error is raised because in pandas the type of a series can be int, str, datetime, float or object. You do not specify any of those types when specifying include.
In fact, you could see it as an error is you would specify these types. For example, suppose we specify that we just want a string series, e.g. data.select_dtypes(include='string'). In this case you'd get an error for other types, e.g.
TypeError: DataFrame must be coercible to a Series
When using the pd.DataFrame constructor there is no need to specify a series type, e.g. data = pd.DataFrame(df) will make the series default to string and the other columns as well.
However, when you do use the pd.DataFrame constructor then it will be necessary to select the series types, e.g.
data = pd.DataFrame(df[['id','Age']], dtype=['int','int'])
So, the answer is that the argument include='string' will work as you'd expect.
Phosphorylation of a myristylated protein by a cdc2-like kinase from mouse embryo.
A cdc2-like 01e38acffe
A:
For part b:
There are several ways to solve this.
One way is the above method of finding the equation of a line that passes through two points and making it parabolic.
The other way is as follows:
Let y = mx + c
Substitute into the quadratic equation to get:
m^2 - 8m + 9 = 0
Using the quadratic formula:
m = ±[sqrt(49)]/2
Now, substitute the value into y = mx + c
y = ±[sqrt(49)]/2 x + c
Solve for c:
c = y - ±[sqrt(49)]/2 x
In an easier example, suppose that you had a circle, and that one of the coordinates were an x-value, and the other was a y-value. You would then write your equation as y = mx + c
How to solve: Substitute in the coordinates into y = mx + c, solve for c, then use the value of c in the final equation. For example: Say you had y = 2x + 7
y = (2x + 7) x + c
= 2x^2 + 14x + 7 x + c
= 2x^2 + 14x + c
Solve for c:
c = 7
Seed germination and growth: a review.
Seeds germinate, grow and flower when irradiated with electron beam at doses of 10-20 Gy. Total irradiation is followed by 'tricellular' growth of seedlings and the transition from seed to seedling. In an optimal irradiation dose range of 100-300 Gy, the rate of seed germination increases significantly. In an optimal irradiation dose range of 600-800 Gy, the rate of seed germination decreases significantly. The percentage of normal seedlings is decreased with a decrease in irradiation dose. Growth rate of normal seedlings increases at doses of 100-300 Gy, with growth rate of the mutated seedlings increasing significantly at doses of 300-800 Gy.The overproduction of polypeptides has many uses in commercial applications, such as production of foods and fuels. Many of the polypeptides produced using microbial fermentation processes are heterologous proteins, that is, they are encoded by genes which are not normally expressed by the producing microorganisms
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